16:I[6874,["874","static/chunks/874-a7ac5a00a7945b42.js","178","static/chunks/178-ab4037c28a81913e.js","844","static/chunks/844-c7a0e2759f5c4b8a.js","99","static/chunks/app/topics/dsa/%5BsubTopicSlug%5D/%5BpostSlug%5D/page-646502347b3d846f.js"],""] 17:I[9844,["874","static/chunks/874-a7ac5a00a7945b42.js","178","static/chunks/178-ab4037c28a81913e.js","844","static/chunks/844-c7a0e2759f5c4b8a.js","99","static/chunks/app/topics/dsa/%5BsubTopicSlug%5D/%5BpostSlug%5D/page-646502347b3d846f.js"],"default"] 18:T4f0,

BFS Basically:

void levelOrderInLine(Node* root) {
    if (root == nullptr) return;
    queue<Node*> q;
    q.push(root);
    
    while (!q.empty()) {
        Node* current = q.front();
        q.pop();
        
        cout << current->data << " ";
        
        if (current->left != nullptr) 
            q.push(current->left);
        if (current->right != nullptr) 
            q.push(current->right);
    }
}

       1
      / \
     2   3
    / \   \
   4   5   6

Initial state:
Queue: [1]
Output: ""

Process 1:
Pop 1 from queue
Print 1
Push left child (2) and right child (3)
Queue: [2, 3]
Output: "1 "

Process 2:
Pop 2 from queue
Print 2
Push left child (4) and right child (5)
Queue: [3, 4, 5]
Output: "1 2 "

Process 3:
Pop 3 from queue
Print 3
Push right child (6) (no left child exists)
Queue: [4, 5, 6]
Output: "1 2 3 "

Process 4:
Pop 4 from queue
Print 4
No children to push
Queue: [5, 6]
Output: "1 2 3 4 "

Process 5:
Pop 5 from queue
Print 5
No children to push
Queue: [6]
Output: "1 2 3 4 5 "

Process 6:
Pop 6 from queue
Print 6
No children to push
Queue: [] (empty)

Final Output: "1 2 3 4 5 6 "

8:["$","div",null,{"className":"post-page-gradient-background","children":["$","article",null,{"className":"container mx-auto px-4 py-12 md:py-16 pt-20","children":["$","div",null,{"className":"max-w-4xl mx-auto mt-8 md:mt-16","children":[["$","header",null,{"className":